could an braced-init-list be a first-class expression?

Newsgroup: comp.lang.c++

Subject: could an braced-init-list be a first-class expression?

From: pietro.cerutti@...

Date: Wed, 19 Feb 2014 10:47:33 -0800 (PST)



I'm wondering what would prevent an initialization list from being a first-class expression of type std::initializer_list.



I understand that the current standar allows braced-init-lists to appear only when assigning to a scalar of type T or to an object of a class taking an std::initializer_list in the assignment operator.



Having



void f (std::vector<double> v);



It is currently possible to do this:



auto a {1, 2, 3}:

g (a);



but not to do this:



g ({1, 2, 3});



As I see it, all information the compiler needs is there. Is there any specific reason why this isn't possible?



Thanks,

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