Difference between pointer to the no data member and the pointer to the first member

Newsgroup: comp.lang.c++

Subject: Difference between pointer to the no data member and the pointer to the first member

From: somenath <somenathpal@...>

Date: Sun, 30 Jun 2013 09:25:24 -0700 (PDT)







I am trying to understanding the difference between the pointer to the no data member and pointer to the first member of class.



Also I have learned that ?The value returned from taking the member?s address, however, is always bumped up by 1?.

To understand this concept I wrote the following simple program.



#include<iostream>

using namespace std;

class A

{

public:

int data;

int data2;



};



int main(void)

{



A a1;

int A::*first_data_member =&A::data;

int A::*second_data_member =&A::data2;

int A::*no_data_member ;

cout<<"no_data_member = "<<(no_data_member)<<endl;

cout<<"first_data_member = "<<(first_data_member)<<endl;

cout<<"second_data_member = "<<(second_data_member)<<endl;





return 0;



}



The output of the above program is as follows.

=================================================

no_data_member = 1

first_data_member = 1

second_data_member = 1



================================================



I am not able to understand the output of the program.



My expectation is if no_data_member is 1 then first_data_member sould be = no_data_member + 1 and second_data_member should be = first_data_member +1.



Please let me know where I am going wrong?

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