Function overloading question

Newsgroup: comp.lang.c++

Subject: Function overloading question

From: blaz.bratanic@...

Date: Thu, 5 Dec 2013 02:40:01 -0800 (PST)



#include <iostream>

#include <vector>

#include <list>



template <typename T>

void foo(T a) {

std::cout << "General" << std::endl;

}



template <typename T>

void foo(std::vector<T> a) {

std::cout << "Vector" << std::endl;

}



int main() {

std::vector<int> v = {1,2,3};

foo(v); // vector



std::list<int> l = {1,2,3};

foo(l); // general

}



Could someone explain does the call to foo not result in an ambiguous call?



Probably the question is, why the compiler prefers

foo<int> over foo<std::vector<int>>?



thanks

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